What is the axis 5x^2+30x+24y=51 ?

The axis 5x^2+30x+24y=51 is x=-3

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axis 5x^2+30x+24y=51

axis

5 x^{2} + 30 x + 24 y = 51

x = - 3

Solution steps

5 x^{2} + 30 x + 24 y = 51

Rewrite

5 x^{2} + 30 x + 24 y = 51

in the standard form

4 (- \frac{6}{5}) (y - 4) = (x - (- 3))^{2}

Therefore parabola properties are:

(h, k) = (- 3, 4), p = - \frac{6}{5}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = - 3

y^{2} - 12 y - 4 x + 28 = 0

y^{2} = 20 x

x^{2} + y^{2} + 4 x - 18 y + 81 = 0

x^{2} = 20 y

y^{2} = 16 x