What is x^2+y^2+4x-18y+81=0 ?

The solution to x^2+y^2+4x-18y+81=0 is Circle with (a,b)=(-2,9),r=2

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x^2+y^2+4x-18y+81=0

x^{2} + y^{2} + 4 x - 18 y + 81 = 0

(a, b) = (- 2, 9), r = 2

Solution steps

x^{2} + y^{2} + 4 x - 18 y + 81 = 0

Rewrite

x^{2} + y^{2} + 4 x - 18 y + 81 = 0

in the form of the standard circle equation

(x - (- 2))^{2} + (y - 9)^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (- 2, 9), r = 2

x^{2} = 20 y

y^{2} = 16 x

y^{2} = - 24 x

9 x^{2} - 16 y^{2} + 36 x + 32 y - 124 = 0

4 x^{2} + 4 y^{2} + 36 y + 5 = 0

What is x^2+y^2+4x-18y+81=0 ?
The solution to x^2+y^2+4x-18y+81=0 is Circle with (a,b)=(-2,9),r=2