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Popular >

foci x^2=16y

Solution

foci

x^{2} = 16 y

Solution

(0, 4)

Solution steps

Rewrite

x^{2} = 16 y

in the standard form:

4 \cdot 4 (y - 0) = (x - 0)^{2}

(h, k) = (0, 0), p = 4

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(0, 0)

along the y-axis

(0, 0 + p)

= (0, 0 + 4)

Refine

(0, 4)

Popular Examples

x^{2} - 2 x - y + 2 = 0

x^2+24x+y^2+10y=-160

x^{2} + 24 x + y^{2} + 10 y = - 160

foci x^2=4y foci

x^{2} = 4 y

(y^2)/4-(x^2)/5 =1

\frac{y ^{2}}{4} - \frac{x ^{2}}{5} = 1

foci 6.25x^2+16y^2-12.5x+64y-29.75=0 foci

6.25 x^{2} + 16 y^{2} - 12.5 x + 64 y - 29.75 = 0

Frequently Asked Questions (FAQ)

What is the foci x^2=16y ?
The foci x^2=16y is (0,4)