What is x^2-2x-y+2=0 ?

The solution to x^2-2x-y+2=0 is Parabola with (h,k)=(1,1),p= 1/4

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x^2-2x-y+2=0

x^{2} - 2 x - y + 2 = 0

(h, k) = (1, 1), p = \frac{1}{4}

Solution steps

x^{2} - 2 x - y + 2 = 0

Rewrite

x^{2} - 2 x - y + 2 = 0

in the standard form

4 \cdot \frac{1}{4} (y - 1) = (x - 1)^{2}

Therefore parabola properties are:

(h, k) = (1, 1), p = \frac{1}{4}

x^{2} + 24 x + y^{2} + 10 y = - 160

x^{2} = 4 y

\frac{y ^{2}}{4} - \frac{x ^{2}}{5} = 1

6.25 x^{2} + 16 y^{2} - 12.5 x + 64 y - 29.75 = 0

4 y^{2} - 25 x^{2} = 100

What is x^2-2x-y+2=0 ?
The solution to x^2-2x-y+2=0 is Parabola with (h,k)=(1,1),p= 1/4