What is (x-1)^2+(y-1)^2=2 ?

The solution to (x-1)^2+(y-1)^2=2 is Circle with (a,b)=(1,1),r=sqrt(2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x-1)^2+(y-1)^2=2

(x - 1)^{2} + (y - 1)^{2} = 2

(a, b) = (1, 1), r = 2

Solution steps

(x - 1)^{2} + (y - 1)^{2} = 2

Rewrite

(x - 1)^{2} + (y - 1)^{2} = 2

in the form of the standard circle equation

(x - 1)^{2} + (y - 1)^{2} = (2)^{2}

Therefore the circle properties are:

(a, b) = (1, 1), r = 2

x^{2} + y^{2} = 5

\frac{x ^{2}}{36} - \frac{y ^{2}}{4} = 1

5 x^{2} + 30 x + 24 y = 51

y^{2} - 12 y - 4 x + 28 = 0

y^{2} = 20 x

What is (x-1)^2+(y-1)^2=2 ?
The solution to (x-1)^2+(y-1)^2=2 is Circle with (a,b)=(1,1),r=sqrt(2)