What is 4x^2+48y+12x-159=0 ?

The solution to 4x^2+48y+12x-159=0 is Parabola with (h,k)=(-3/2 , 7/2),p=-3

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4x^2+48y+12x-159=0

4 x^{2} + 48 y + 12 x - 159 = 0

(h, k) = (- \frac{3}{2}, \frac{7}{2}), p = - 3

Solution steps

4 x^{2} + 48 y + 12 x - 159 = 0

Rewrite

4 x^{2} + 48 y + 12 x - 159 = 0

in the standard form

4 (- 3) (y - \frac{7}{2}) = (x - (- \frac{3}{2}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{3}{2}, \frac{7}{2}), p = - 3

y - 3 x^{2} + 10 x = 5

x, 2 x^{2} + 5 x + 2 = - 3 (2 w + 1)

x^{2} - 8 y + 8 = 0

y = 0.5 x^{2} - 3

5 y^{2} + 2 x - 21 y + 20 = 0

What is 4x^2+48y+12x-159=0 ?
The solution to 4x^2+48y+12x-159=0 is Parabola with (h,k)=(-3/2 , 7/2),p=-3