What is 7x^2+5x-k(x)=0 ?

The solution to 7x^2+5x-k(x)=0 is Parabola with (h,k)=(-5/14 ,-25/28),p= 1/28

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7x^2+5x-k(x)=0

7 x^{2} + 5 x - k (x) = 0

(h, k) = (- \frac{5}{14}, - \frac{25}{28}), p = \frac{1}{28}

Solution steps

7 x^{2} + 5 x - y = 0

Rewrite

7 x^{2} + 5 x - y = 0

in the standard form

4 \cdot \frac{1}{28} (y - (- \frac{25}{28})) = (x - (- \frac{5}{14}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{5}{14}, - \frac{25}{28}), p = \frac{1}{28}

x^{2} - 16 y - 4 x - 12 = 0

(x - 5)^{2} = - 29 (y - 1)

x, \frac{9}{u ( x ) ^{3}} = \frac{x}{5 u ( x ) ^{5}}

x^{2} - 6 x - 24 y - 15 = 0

y = 21 x^{2} + 4 x + 9

What is 7x^2+5x-k(x)=0 ?
The solution to 7x^2+5x-k(x)=0 is Parabola with (h,k)=(-5/14 ,-25/28),p= 1/28