What is x^2-16y-4x-12=0 ?

The solution to x^2-16y-4x-12=0 is Parabola with (h,k)=(2,-1),p=4

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x^2-16y-4x-12=0

x^{2} - 16 y - 4 x - 12 = 0

(h, k) = (2, - 1), p = 4

Solution steps

x^{2} - 16 y - 4 x - 12 = 0

Rewrite

x^{2} - 16 y - 4 x - 12 = 0

in the standard form

4 \cdot 4 (y - (- 1)) = (x - 2)^{2}

Therefore parabola properties are:

(h, k) = (2, - 1), p = 4

(x - 5)^{2} = - 29 (y - 1)

x, \frac{9}{u ( x ) ^{3}} = \frac{x}{5 u ( x ) ^{5}}

x^{2} - 6 x - 24 y - 15 = 0

y = 21 x^{2} + 4 x + 9

10 x + y = - x^{2} + 2

What is x^2-16y-4x-12=0 ?
The solution to x^2-16y-4x-12=0 is Parabola with (h,k)=(2,-1),p=4