en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci y= 1/4 x^2

Solution

foci

y = \frac{1}{4} x^{2}

Solution

(0, 1)

Solution steps

Rewrite

y = \frac{1}{4} x^{2}

in the standard form:

4 \cdot 1 \cdot (y - 0) = (x - 0)^{2}

(h, k) = (0, 0), p = 1

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(0, 0)

along the y-axis

(0, 0 + p)

= (0, 0 + 1)

Refine

(0, 1)

Popular Examples

asymptotes of 9x^2-4y^2-90x-32y=-305 asymptotes

9 x^{2} - 4 y^{2} - 90 x - 32 y = - 305

vertices f(x)=x^2-6x+2 vertices

f (x) = x^{2} - 6 x + 2

(y^2)/(25)-(x^2)/(16)=1

\frac{y ^{2}}{25} - \frac{x ^{2}}{16} = 1

((x+3)^2)/(16)+((y-5)^2)/(25)=1

\frac{( x + 3 ) ^{2}}{16} + \frac{( y - 5 ) ^{2}}{25} = 1

eccentricity 9x^2+y^2=9 eccentricity

9 x^{2} + y^{2} = 9

Frequently Asked Questions (FAQ)

What is the foci y= 1/4 x^2 ?
The foci y= 1/4 x^2 is (0,1)