What is (y^2)/(25)-(x^2)/(16)=1 ?

The solution to (y^2)/(25)-(x^2)/(16)=1 is Hyperbola with (h,k)=(0,0),a=5,b=4

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(y^2)/(25)-(x^2)/(16)=1

\frac{y ^{2}}{25} - \frac{x ^{2}}{16} = 1

(h, k) = (0, 0), a = 5, b = 4

Solution steps

\frac{y ^{2}}{25} - \frac{x ^{2}}{16} = 1

Rewrite

\frac{y ^{2}}{25} - \frac{x ^{2}}{16} = 1

in the form of a standard hyperbola equation

\frac{( y - 0 ) ^{2}}{5 ^{2}} - \frac{( x - 0 ) ^{2}}{4 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 5, b = 4

\frac{( x + 3 ) ^{2}}{16} + \frac{( y - 5 ) ^{2}}{25} = 1

9 x^{2} + y^{2} = 9

y \geq x^{2}

x^{2} + 4 x + 4 y - 4 = 0

x^{2} + 8 y = 0

What is (y^2)/(25)-(x^2)/(16)=1 ?
The solution to (y^2)/(25)-(x^2)/(16)=1 is Hyperbola with (h,k)=(0,0),a=5,b=4