What is x^2=-125/16 (y-20) ?

The solution to x^2=-125/16 (y-20) is Parabola with (h,k)=(0,20),p=-125/64

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x^2=-125/16 (y-20)

x^{2} = - \frac{125}{16} (y - 20)

(h, k) = (0, 20), p = - \frac{125}{64}

Solution steps

x^{2} = - \frac{125}{16} (y - 20)

Rewrite

x^{2} = - \frac{125}{16} (y - 20)

in the standard form:

4 (- \frac{125}{64}) (y - 20) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 20), p = - \frac{125}{64}

(x - 0)^{2} = 8 (y - 0)

- x^{2} - y = 2

- 2 x^{2} - 20 x + y - 46 = 0

(y + 3)^{2} = \frac{1}{2} (x + 16)

x^{2} = 20 + y

What is x^2=-125/16 (y-20) ?
The solution to x^2=-125/16 (y-20) is Parabola with (h,k)=(0,20),p=-125/64