What is (y+3)^2= 1/2 (x+16) ?

The solution to (y+3)^2= 1/2 (x+16) is Parabola with (h,k)=(-16,-3),p= 1/8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(y+3)^2= 1/2 (x+16)

(y + 3)^{2} = \frac{1}{2} (x + 16)

(h, k) = (- 16, - 3), p = \frac{1}{8}

Solution steps

(y + 3)^{2} = \frac{1}{2} (x + 16)

Rewrite

(y + 3)^{2} = \frac{1}{2} (x + 16)

in the standard form:

4 \cdot \frac{1}{8} (x - (- 16)) = (y - (- 3))^{2}

Therefore parabola properties are:

(h, k) = (- 16, - 3), p = \frac{1}{8}

x^{2} = 20 + y

(X - 3)^{2} = - 4 (y - 1)

2 + y^{2} + 8 x - 14 y + 1 = 0

x = 4 + 6 y - 2 y^{2}

(y + 2)^{2} = 4 (x - 6)

What is (y+3)^2= 1/2 (x+16) ?
The solution to (y+3)^2= 1/2 (x+16) is Parabola with (h,k)=(-16,-3),p= 1/8