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foci
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Calculate Hyperbola properties
Right-left Hyperbola with
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Popular Examples
vertices f(x)=x^2+4x+1vertices (x^2)/9-(y^2)/(25)=1directrix x-2= 1/8 (y+1)^2directrix y=2x^2vertices (y^2)/9-(x^2)/(16)=1
Frequently Asked Questions (FAQ)
What is the foci x^2-y^2=6 ?
The foci x^2-y^2=6 is (2sqrt(3),0),(-2sqrt(3),0)