What is the asymptotes of 9x^2-4y^2+72x+180=0 ?

The asymptotes of 9x^2-4y^2+72x+180=0 is y= 3/2 (x+4),\quad y=-3/2 (x+4)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

asymptotes of 9x^2-4y^2+72x+180=0

asymptotes

y = \frac{3}{2} (x + 4), y = - \frac{3}{2} (x + 4)

Solution steps

y = \pm \frac{a}{b} (x - h) + k

Calculate Hyperbola properties

9 x^{2} - 4 y^{2} + 72 x + 180 = 0 :

Up-down Hyperbola with

(h, k) = (- 4, 0), a = 3, b = 2

y = \frac{3}{2} (x - (- 4)) + 0, y = - \frac{3}{2} (x - (- 4)) + 0

Refine

y = \frac{3}{2} (x + 4), y = - \frac{3}{2} (x + 4)

What is the asymptotes of 9x^2-4y^2+72x+180=0 ?
The asymptotes of 9x^2-4y^2+72x+180=0 is y= 3/2 (x+4),\quad y=-3/2 (x+4)