What is the asymptotes of 8y^2-32x^2=96 ?

The asymptotes of 8y^2-32x^2=96 is y=2x,\quad y=-2x

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asymptotes of 8y^2-32x^2=96

asymptotes

8 y^{2} - 32 x^{2} = 96

y = 2 x, y = - 2 x

Solution steps

y = \pm \frac{a}{b} (x - h) + k

Calculate Hyperbola properties

8 y^{2} - 32 x^{2} = 96 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 23, b = 3

y = \frac{2 3}{3} (x - 0) + 0, y = - \frac{2 3}{3} (x - 0) + 0

Refine

y = 2 x, y = - 2 x

9 x^{2} - y^{2} + 36 x - 2 y = 46

x^{2} - y^{2} + 6 x = 41

\frac{( y ) ^{2}}{4} - \frac{( x ) ^{2}}{16} = 1

(x - 8)^{2} - (y + 6)^{2} = 1

4 x^{2} - 9 y^{2} - 18 y - 153 = 0

What is the asymptotes of 8y^2-32x^2=96 ?
The asymptotes of 8y^2-32x^2=96 is y=2x,\quad y=-2x