渐近线 y^2=x^2-1

解答

渐近线

y^{2} = x^{2} - 1

y = x, y = - x

求解步骤

y = \pm \frac{a}{b} (x - h) + k

计算双曲线性质

y^{2} = x^{2} - 1 :

上下开口双曲线，

(h, k) = (0, 0), a = 1, b = 1

y = \frac{1}{1} (x - 0) + 0, y = - \frac{1}{1} (x - 0) + 0

整理后得

y = x, y = - x

a sy m pt o t es \frac{( y + 2 ) ^{2}}{36} - x^{2} = 1

a sy m pt o t es 0 = - \frac{400}{9} x^{2} + 16 y^{2} + 400

a sy m pt o t es \frac{x ^{2}}{16} - \frac{y ^{2}}{25} = 1

a sy m pt o t es 9 x^{2} - 18 x - 16 y^{2} - 64 y = 199

a sy m pt o t es \frac{x ^{2}}{4} - \frac{y ^{2}}{5} = 1