渐近线 (x^2)/4-(y^2)/5 =1

解答

渐近线

\frac{x ^{2}}{4} - \frac{y ^{2}}{5} = 1

y = \frac{5 x}{2}, y = - \frac{5 x}{2}

求解步骤

y = \pm \frac{b}{a} (x - h) + k

计算双曲线性质

\frac{x ^{2}}{4} - \frac{y ^{2}}{5} = 1 :

左右开口双曲线，

(h, k) = (0, 0), a = 2, b = 5

y = \frac{5}{2} (x - 0) + 0, y = - \frac{5}{2} (x - 0) + 0

整理后得

y = \frac{5 x}{2}, y = - \frac{5 x}{2}

a sy m pt o t es x^{2} - y^{2} + 4 x - 6 y = 6

a sy m pt o t es 9 x^{2} - 4 y^{2} + 36 x - 8 y - 40 = 0

a sy m pt o t es \frac{y ^{2}}{16} - \frac{x ^{2}}{1} = 1

a sy m pt o t es 4 x^{2} - y^{2} = 2

a sy m pt o t es 4 x^{2} - y^{2} = 4