What is the foci x^2-16y^2=16 ?

The foci x^2-16y^2=16 is (sqrt(17),0),(-sqrt(17),0)

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foci x^2-16y^2=16

foci

x^{2} - 16 y^{2} = 16

(17, 0), (- 17, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

x^{2} - 16 y^{2} = 16 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 4, b = 1

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 4^{2} + 1^{2} : 17

(0 + 17, 0), (0 - 17, 0)

Refine

(17, 0), (- 17, 0)

3 x^{2} - y^{2} = 11

\frac{y ^{2}}{1 2 ^{2}} - \frac{x ^{2}}{5 ^{2}} = 1

y^{2} - 4 x^{2} - 10 y - 40 x - 100 = 0

- 1 = x^{2} - y^{2}

\frac{( x ^{2} )}{4} - 0.15 y^{2} = 1

What is the foci x^2-16y^2=16 ?
The foci x^2-16y^2=16 is (sqrt(17),0),(-sqrt(17),0)