What is the foci ((x^2))/4-0.15y^2=1 ?

The foci ((x^2))/4-0.15y^2=1 is (3.26598…,0),(-3.26598…,0)

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foci ((x^2))/4-0.15y^2=1

foci

\frac{( x ^{2} )}{4} - 0.15 y^{2} = 1

(3.26598 \dots, 0), (- 3.26598 \dots, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

\frac{x ^{2}}{4} - 0.15 y^{2} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 2, b = 2.58198 \dots

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 2^{2} + 2.58198 \dots^{2} : 3.26598 \dots

(0 + 3.26598 \dots, 0), (0 - 3.26598 \dots, 0)

Refine

(3.26598 \dots, 0), (- 3.26598 \dots, 0)

9 x^{2} - y^{2} - 36 x - 6 y + 18 = 0

\frac{x ^{2}}{4} - \frac{( y + 1 ) ^{2}}{16} = 1

\frac{( x - 5 ) ^{2}}{4} - \frac{( y + 5 ) ^{2}}{9} = 1

\frac{( x - 1 ) ^{2}}{4} - \frac{( y - 2 ) ^{2}}{1} = 1

y^{2} - x^{2} = 1

What is the foci ((x^2))/4-0.15y^2=1 ?
The foci ((x^2))/4-0.15y^2=1 is (3.26598…,0),(-3.26598…,0)