What is the foci-4x^2+y^2+40x-136=0 ?

The foci-4x^2+y^2+40x-136=0 is (5,3sqrt(5)),(5,-3sqrt(5))

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foci-4x^2+y^2+40x-136=0

foci

- 4 x^{2} + y^{2} + 40 x - 136 = 0

(5, 35), (5, - 35)

Solution steps

(h, k + c), (h, k - c)

Calculate Hyperbola properties

- 4 x^{2} + y^{2} + 40 x - 136 = 0 :

Up-down Hyperbola with

(h, k) = (5, 0), a = 6, b = 3

(5, 0 + c), (5, 0 - c)

Compute

c :

c = 6^{2} + 3^{2} : 35

(5, 0 + 35), (5, 0 - 35)

Refine

(5, 35), (5, - 35)

\frac{y ^{2}}{225} - \frac{x ^{2}}{324} = 1

- x^{2} + 8 x + 4 y^{2} - 40 y + 88 = 0

\frac{( y + 2 ) ^{2}}{36} - x^{2} = 1

\frac{x ^{2}}{23} - \frac{y ^{2}}{2} = 1

9 x^{2} - 16 y^{2} - 18 x + 64 y - 199 = 0

What is the foci-4x^2+y^2+40x-136=0 ?
The foci-4x^2+y^2+40x-136=0 is (5,3sqrt(5)),(5,-3sqrt(5))