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foci
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Calculate Hyperbola properties
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foci (y^2)/(225)-(x^2)/(324)=1foci-x^2+8x+4y^2-40y+88=0foci ((y+2)^2)/(36)-x^2=1foci (x^2}{23}-\frac{y^2)/2 =1foci 9x^2-16y^2-18x+64y-199=0
Frequently Asked Questions (FAQ)
What is the foci-4x^2+y^2+40x-136=0 ?
The foci-4x^2+y^2+40x-136=0 is (5,3sqrt(5)),(5,-3sqrt(5))