What is the foci (x^2}{23}-\frac{y^2)/2 =1 ?

The foci (x^2}{23}-\frac{y^2)/2 =1 is (5,0),(-5,0)

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foci (x^2}{23}-\frac{y^2)/2 =1

foci

\frac{x ^{2}}{23} - \frac{y ^{2}}{2} = 1

(5, 0), (- 5, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

\frac{x ^{2}}{23} - \frac{y ^{2}}{2} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 23, b = 2

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 23^{2} + 2^{2} : 5

(0 + 5, 0), (0 - 5, 0)

Refine

(5, 0), (- 5, 0)

9 x^{2} - 16 y^{2} - 18 x + 64 y - 199 = 0

49 y^{2} - 100 x^{2} = 4900

\frac{x ^{2}}{64} - \frac{y ^{2}}{4} = 1

\frac{( x - 1 ) ^{2}}{25} - \frac{( y - 2 ) ^{2}}{16} = 1

9 x^{2} - 16 y^{2} - 108 x + 64 y + 116 = 0

What is the foci (x^2}{23}-\frac{y^2)/2 =1 ?
The foci (x^2}{23}-\frac{y^2)/2 =1 is (5,0),(-5,0)