What is the foci ((x^2))/(36)-((y^2))/(25)=1 ?

The foci ((x^2))/(36)-((y^2))/(25)=1 is (sqrt(61),0),(-sqrt(61),0)

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foci ((x^2))/(36)-((y^2))/(25)=1

foci

(61, 0), (- 61, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

\frac{x ^{2}}{36} - \frac{y ^{2}}{25} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 6, b = 5

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 6^{2} + 5^{2} : 61

(0 + 61, 0), (0 - 61, 0)

Refine

(61, 0), (- 61, 0)

What is the foci ((x^2))/(36)-((y^2))/(25)=1 ?
The foci ((x^2))/(36)-((y^2))/(25)=1 is (sqrt(61),0),(-sqrt(61),0)