What is the foci y^2-x^2= 1/25 ?

The foci y^2-x^2= 1/25 is (0,(sqrt(2))/5),(0,-(sqrt(2))/5)

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foci y^2-x^2= 1/25

foci

y^{2} - x^{2} = \frac{1}{25}

(0, \frac{2}{5}), (0, - \frac{2}{5})

Solution steps

(h, k + c), (h, k - c)

Calculate Hyperbola properties

y^{2} - x^{2} = \frac{1}{25} :

Up-down Hyperbola with

(h, k) = (0, 0), a = \frac{1}{5}, b = \frac{1}{5}

(0, 0 + c), (0, 0 - c)

Compute

c :

c = (\frac{1}{5})^{2} + (\frac{1}{5})^{2} : \frac{2}{5}

(0, 0 + \frac{2}{5}), (0, 0 - \frac{2}{5})

Refine

(0, \frac{2}{5}), (0, - \frac{2}{5})

y^{2} - 4 x^{2} < 1

x^{2} - 16 y^{2} = 64

(\frac{( x ^{2} )}{27}) - \frac{( ( y ) ^{2} )}{36} = 1

x^{2} - y^{2} - 6 x + 16 y - 119 = 0

9 x^{2} - 25 y^{2} = 900

What is the foci y^2-x^2= 1/25 ?
The foci y^2-x^2= 1/25 is (0,(sqrt(2))/5),(0,-(sqrt(2))/5)