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foci
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Calculate Hyperbola properties
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foci (x^2)/(144)-(y^2)/(81)=1foci (y^2)/(25)-(x^2)/(49)=1foci-9x^2+y^2+54x-117=0foci ((y^2)}{27}-\frac{(x^2))/9 =1foci 64x^2-100y^2=6400
Frequently Asked Questions (FAQ)
What is the foci 16x^2-9y^2-64x-18y+199=0 ?
The foci 16x^2-9y^2-64x-18y+199=0 is (2,4),(2,-6)