What is the foci ((y-1)^2)/4-((x+8)^2)/(25)=1 ?

The foci ((y-1)^2)/4-((x+8)^2)/(25)=1 is (-8,1+sqrt(29)),(-8,1-sqrt(29))

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foci ((y-1)^2)/4-((x+8)^2)/(25)=1

foci

(- 8, 1 + 29), (- 8, 1 - 29)

Solution steps

(h, k + c), (h, k - c)

Calculate Hyperbola properties

\frac{( y - 1 ) ^{2}}{4} - \frac{( x + 8 ) ^{2}}{25} = 1 :

Up-down Hyperbola with

(h, k) = (- 8, 1), a = 2, b = 5

(- 8, 1 + c), (- 8, 1 - c)

Compute

c :

c = 2^{2} + 5^{2} : 29

(- 8, 1 + 29), (- 8, 1 - 29)

What is the foci ((y-1)^2)/4-((x+8)^2)/(25)=1 ?
The foci ((y-1)^2)/4-((x+8)^2)/(25)=1 is (-8,1+sqrt(29)),(-8,1-sqrt(29))