What is the foci (x^2)/4-(y^2)/(49)=1 ?

The foci (x^2)/4-(y^2)/(49)=1 is (sqrt(53),0),(-sqrt(53),0)

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foci (x^2)/4-(y^2)/(49)=1

foci

(53, 0), (- 53, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

\frac{x ^{2}}{4} - \frac{y ^{2}}{49} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 2, b = 7

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 2^{2} + 7^{2} : 53

(0 + 53, 0), (0 - 53, 0)

Refine

(53, 0), (- 53, 0)

What is the foci (x^2)/4-(y^2)/(49)=1 ?
The foci (x^2)/4-(y^2)/(49)=1 is (sqrt(53),0),(-sqrt(53),0)