What is the foci (x^2)/8-(y^2)/8 =1 ?

The foci (x^2)/8-(y^2)/8 =1 is (4,0),(-4,0)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

foci (x^2)/8-(y^2)/8 =1

foci

(4, 0), (- 4, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

\frac{x ^{2}}{8} - \frac{y ^{2}}{8} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 22, b = 22

(0 + c, 0), (0 - c, 0)

Compute

c :

c = (22)^{2} + (22)^{2} : 4

(0 + 4, 0), (0 - 4, 0)

Refine

(4, 0), (- 4, 0)

What is the foci (x^2)/8-(y^2)/8 =1 ?
The foci (x^2)/8-(y^2)/8 =1 is (4,0),(-4,0)