What is the foci+(x^2)/4-(y^2)/4 =1 ?

The foci+(x^2)/4-(y^2)/4 =1 is (2sqrt(2),0),(-2sqrt(2),0)

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foci+(x^2)/4-(y^2)/4 =1

foci

(22, 0), (- 22, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

+ \frac{x ^{2}}{4} - \frac{y ^{2}}{4} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 2, b = 2

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 2^{2} + 2^{2} : 22

(0 + 22, 0), (0 - 22, 0)

Refine

(22, 0), (- 22, 0)

What is the foci+(x^2)/4-(y^2)/4 =1 ?
The foci+(x^2)/4-(y^2)/4 =1 is (2sqrt(2),0),(-2sqrt(2),0)