What is the foci 25x^2-16y^2+250x+32y+109=0 ?

The foci 25x^2-16y^2+250x+32y+109=0 is ((-10+sqrt(205))/2 ,1),((-10-sqrt(205))/2 ,1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

foci 25x^2-16y^2+250x+32y+109=0

foci

(\frac{- 10 + 205}{2}, 1), (\frac{- 10 - 205}{2}, 1)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

25 x^{2} - 16 y^{2} + 250 x + 32 y + 109 = 0 :

Right-left Hyperbola with

(h, k) = (- 5, 1), a = 25, b = \frac{5 5}{2}

(- 5 + c, 1), (- 5 - c, 1)

Compute

c :

c = (25)^{2} + (\frac{5 5}{2})^{2} : \frac{205}{2}

(- 5 + \frac{205}{2}, 1), (- 5 - \frac{205}{2}, 1)

Refine

(\frac{- 10 + 205}{2}, 1), (\frac{- 10 - 205}{2}, 1)

What is the foci 25x^2-16y^2+250x+32y+109=0 ?
The foci 25x^2-16y^2+250x+32y+109=0 is ((-10+sqrt(205))/2 ,1),((-10-sqrt(205))/2 ,1)