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foci
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Calculate Hyperbola properties
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Popular Examples
foci y^2-4x^2+4x-2y-4=0foci 5x^2-4y^2+80=0foci+9x^2-y^2-36x-6y+18=0foci ((y+5)^2}{16}-\frac{(x+3)^2)/9 =1foci ((y+5)^2)/(1/9)-((x-3)^2)/(1/4)=1
Frequently Asked Questions (FAQ)
What is the foci (y^2)/4-(x^2)/1 =1 ?
The foci (y^2)/4-(x^2)/1 =1 is (0,sqrt(5)),(0,-sqrt(5))