What is the foci 9(y-2)^2-4x^2=36 ?

The foci 9(y-2)^2-4x^2=36 is (0,2+sqrt(13)),(0,2-sqrt(13))

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foci 9(y-2)^2-4x^2=36

foci

(0, 2 + 13), (0, 2 - 13)

Solution steps

(h, k + c), (h, k - c)

Calculate Hyperbola properties

9 (y - 2)^{2} - 4 x^{2} = 36 :

Up-down Hyperbola with

(h, k) = (0, 2), a = 2, b = 3

(0, 2 + c), (0, 2 - c)

Compute

c :

c = 2^{2} + 3^{2} : 13

(0, 2 + 13), (0, 2 - 13)

What is the foci 9(y-2)^2-4x^2=36 ?
The foci 9(y-2)^2-4x^2=36 is (0,2+sqrt(13)),(0,2-sqrt(13))