What is the vertices (y^2)/(25)-(x^2)/(81)=1 ?

The vertices (y^2)/(25)-(x^2)/(81)=1 is (0,5),(0,-5)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

vertices (y^2)/(25)-(x^2)/(81)=1

vertices

\frac{y ^{2}}{25} - \frac{x ^{2}}{81} = 1

(0, 5), (0, - 5)

Solution steps

(h, k + a), (h, k - a)

Calculate Hyperbola properties

\frac{y ^{2}}{25} - \frac{x ^{2}}{81} = 1 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 5, b = 9

(0, 0 + 5), (0, 0 - 5)

Refine

(0, 5), (0, - 5)

9 x^{2} - 18 x - 16 y^{2} - 64 y = 199

\frac{y ^{2}}{49} - \frac{x ^{2}}{16} = 1

- 3 x^{2} + 2 y^{2} + 6 x - 7 y = 7

\frac{( y - 3 ) ^{2}}{49} - \frac{( x + 2 ) ^{2}}{16} = 1

x^{2} - y^{2} - 4 x + 8 y - 21 = 0

What is the vertices (y^2)/(25)-(x^2)/(81)=1 ?
The vertices (y^2)/(25)-(x^2)/(81)=1 is (0,5),(0,-5)