What is the vertices ((x+5)^2)/4-(y^2)/4 =1 ?

The vertices ((x+5)^2)/4-(y^2)/4 =1 is (-3,0),(-7,0)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

vertices ((x+5)^2)/4-(y^2)/4 =1

vertices

\frac{( x + 5 ) ^{2}}{4} - \frac{y ^{2}}{4} = 1

(- 3, 0), (- 7, 0)

Solution steps

(h + a, k), (h - a, k)

Calculate Hyperbola properties

\frac{( x + 5 ) ^{2}}{4} - \frac{y ^{2}}{4} = 1 :

Right-left Hyperbola with

(h, k) = (- 5, 0), a = 2, b = 2

(- 5 + 2, 0), (- 5 - 2, 0)

Refine

(- 3, 0), (- 7, 0)

- 9 x^{2} + 8 y^{2} + 36 x + 48 y = 36

36 x^{2} - y^{2} - 216 x + 10 y + 263 = 0

4 x^{2} - 9 y^{2} - 36 = 0

9 x^{2} - 4 y^{2} - 54 x - 16 y + 29 = 0

25 x^{2} - 16 y^{2} + 50 x + 128 y - 631 = 0

What is the vertices ((x+5)^2)/4-(y^2)/4 =1 ?
The vertices ((x+5)^2)/4-(y^2)/4 =1 is (-3,0),(-7,0)