What is the vertices 36x^2-y^2-216x+10y+263=0 ?

The vertices 36x^2-y^2-216x+10y+263=0 is (4,5),(2,5)

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vertices 36x^2-y^2-216x+10y+263=0

vertices

36 x^{2} - y^{2} - 216 x + 10 y + 263 = 0

(4, 5), (2, 5)

Solution steps

(h + a, k), (h - a, k)

Calculate Hyperbola properties

36 x^{2} - y^{2} - 216 x + 10 y + 263 = 0 :

Right-left Hyperbola with

(h, k) = (3, 5), a = 1, b = 6

(3 + 1, 5), (3 - 1, 5)

Refine

(4, 5), (2, 5)

4 x^{2} - 9 y^{2} - 36 = 0

9 x^{2} - 4 y^{2} - 54 x - 16 y + 29 = 0

25 x^{2} - 16 y^{2} + 50 x + 128 y - 631 = 0

x^{2} - y^{2} + 7 x + 8 y = 5

16 x^{2} - 25 y^{2} = 400

What is the vertices 36x^2-y^2-216x+10y+263=0 ?
The vertices 36x^2-y^2-216x+10y+263=0 is (4,5),(2,5)