What is ((y+3)^2)/(81)-((x+3)^2)/(16)=1 ?

The solution to ((y+3)^2)/(81)-((x+3)^2)/(16)=1 is Hyperbola with (h,k)=(-3,-3),a=9,b=4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

((y+3)^2)/(81)-((x+3)^2)/(16)=1

\frac{( y + 3 ) ^{2}}{81} - \frac{( x + 3 ) ^{2}}{16} = 1

(h, k) = (- 3, - 3), a = 9, b = 4

Solution steps

\frac{( y + 3 ) ^{2}}{81} - \frac{( x + 3 ) ^{2}}{16} = 1

Rewrite

\frac{( y + 3 ) ^{2}}{81} - \frac{( x + 3 ) ^{2}}{16} = 1

in the form of a standard hyperbola equation

\frac{( y - ( - 3 ) ) ^{2}}{9 ^{2}} - \frac{( x - ( - 3 ) ) ^{2}}{4 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 3, - 3), a = 9, b = 4

(x - 4)^{2} - (y - 4)^{2} \leq 9

x^{2} + x = y^{2}

\frac{( x ^{(2)} )}{( 9 )} - \frac{( y ^{(2)} )}{( 16 )} = 1

y^{2} - 4 z^{2} = 4

- \frac{y ^{2}}{4} + \frac{z ^{2}}{4} = 1

What is ((y+3)^2)/(81)-((x+3)^2)/(16)=1 ?
The solution to ((y+3)^2)/(81)-((x+3)^2)/(16)=1 is Hyperbola with (h,k)=(-3,-3),a=9,b=4