What is -(y^2)/4+(z^2)/4 =1 ?

The solution to -(y^2)/4+(z^2)/4 =1 is Hyperbola with (h,k)=(0,0),a=2,b=2

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-(y^2)/4+(z^2)/4 =1

- \frac{y ^{2}}{4} + \frac{z ^{2}}{4} = 1

(h, k) = (0, 0), a = 2, b = 2

Solution steps

- \frac{y ^{2}}{4} + \frac{z ^{2}}{4} = 1

Rewrite

- \frac{y ^{2}}{4} + \frac{z ^{2}}{4} = 1

in the form of a standard hyperbola equation

\frac{( z - 0 ) ^{2}}{2 ^{2}} - \frac{( y - 0 ) ^{2}}{2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 2, b = 2

\frac{( y + 2 ) ^{2}}{4} - \frac{( x - 1 ) ^{2}}{64} = 1

(y - 1)^{2} - 9 (x - 2)^{2} = 9

y^{2} = (- x)^{2} + 6

\frac{4 b - 4 a}{b - a} = (a^{2} - b^{2})

\frac{x ^{2}}{25} - y^{2} = 1

What is -(y^2)/4+(z^2)/4 =1 ?
The solution to -(y^2)/4+(z^2)/4 =1 is Hyperbola with (h,k)=(0,0),a=2,b=2