What is ((x-5)/4)^2-((y+7)/3)^2=-1 ?

The solution to ((x-5)/4)^2-((y+7)/3)^2=-1 is Hyperbola with (h,k)=(5,-7),a=3,b=4

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((x-5)/4)^2-((y+7)/3)^2=-1

(\frac{x - 5}{4})^{2} - (\frac{y + 7}{3})^{2} = - 1

(h, k) = (5, - 7), a = 3, b = 4

Solution steps

(\frac{x - 5}{4})^{2} - (\frac{y + 7}{3})^{2} = - 1

Rewrite

(\frac{x - 5}{4})^{2} - (\frac{y + 7}{3})^{2} = - 1

in the form of a standard hyperbola equation

\frac{( y - ( - 7 ) ) ^{2}}{3 ^{2}} - \frac{( x - 5 ) ^{2}}{4 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (5, - 7), a = 3, b = 4

y^{2} = (x - 4)^{2} + 4

\frac{( y - 1 ) ^{2}}{4} - \frac{( x + 4 ) ^{2}}{9} = 1

3 (x - 2)^{(2)} - 2 (y - 2)^{(2)} = - 11

2 x^{2} - 6 y^{2} + 14 = 0

(x + y) (x - y) \geq 1

What is ((x-5)/4)^2-((y+7)/3)^2=-1 ?
The solution to ((x-5)/4)^2-((y+7)/3)^2=-1 is Hyperbola with (h,k)=(5,-7),a=3,b=4