What is ((y-1)^2)/4-((x+4)^2)/9 =1 ?

The solution to ((y-1)^2)/4-((x+4)^2)/9 =1 is Hyperbola with (h,k)=(-4,1),a=2,b=3

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((y-1)^2)/4-((x+4)^2)/9 =1

\frac{( y - 1 ) ^{2}}{4} - \frac{( x + 4 ) ^{2}}{9} = 1

(h, k) = (- 4, 1), a = 2, b = 3

Solution steps

\frac{( y - 1 ) ^{2}}{4} - \frac{( x + 4 ) ^{2}}{9} = 1

Rewrite

\frac{( y - 1 ) ^{2}}{4} - \frac{( x + 4 ) ^{2}}{9} = 1

in the form of a standard hyperbola equation

\frac{( y - 1 ) ^{2}}{2 ^{2}} - \frac{( x - ( - 4 ) ) ^{2}}{3 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 4, 1), a = 2, b = 3

3 (x - 2)^{(2)} - 2 (y - 2)^{(2)} = - 11

2 x^{2} - 6 y^{2} + 14 = 0

(x + y) (x - y) \geq 1

16 x^{2} - 9 y^{2} + 96 x - 72 y + 144 = 0

\frac{x ^{2}}{81} - \frac{y ^{2}}{61} = 1

What is ((y-1)^2)/4-((x+4)^2)/9 =1 ?
The solution to ((y-1)^2)/4-((x+4)^2)/9 =1 is Hyperbola with (h,k)=(-4,1),a=2,b=3