What is (x^2)/(58)-(y^2)/(120)=1 ?

The solution to (x^2)/(58)-(y^2)/(120)=1 is Hyperbola with (h,k)=(0,0),a=sqrt(58),b=2sqrt(30)

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(x^2)/(58)-(y^2)/(120)=1

\frac{x ^{2}}{58} - \frac{y ^{2}}{120} = 1

(h, k) = (0, 0), a = 58, b = 230

Solution steps

\frac{x ^{2}}{58} - \frac{y ^{2}}{120} = 1

Rewrite

\frac{x ^{2}}{58} - \frac{y ^{2}}{120} = 1

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{( 58 ) ^{2}} - \frac{( y - 0 ) ^{2}}{( 2 30 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 58, b = 230

\frac{( x - 5 ) ^{2}}{36} - \frac{( y - 2 ) ^{2}}{16} = 1

y^{2} - 9 x^{2} - 4 y + 18 x = 86

y^{2} - 4 x^{2} + 8 x = 20 y + 4

\frac{x ^{2}}{4} - \frac{y ^{2}}{32} = 1

16 x^{2} - 9 y^{2} - 32 x + 36 y + 124 = 0

What is (x^2)/(58)-(y^2)/(120)=1 ?
The solution to (x^2)/(58)-(y^2)/(120)=1 is Hyperbola with (h,k)=(0,0),a=sqrt(58),b=2sqrt(30)