What is ((x-5)^2)/(36)-((y-2)^2)/(16)=1 ?

The solution to ((x-5)^2)/(36)-((y-2)^2)/(16)=1 is Hyperbola with (h,k)=(5,2),a=6,b=4

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((x-5)^2)/(36)-((y-2)^2)/(16)=1

\frac{( x - 5 ) ^{2}}{36} - \frac{( y - 2 ) ^{2}}{16} = 1

(h, k) = (5, 2), a = 6, b = 4

Solution steps

\frac{( x - 5 ) ^{2}}{36} - \frac{( y - 2 ) ^{2}}{16} = 1

Rewrite

\frac{( x - 5 ) ^{2}}{36} - \frac{( y - 2 ) ^{2}}{16} = 1

in the form of a standard hyperbola equation

\frac{( x - 5 ) ^{2}}{6 ^{2}} - \frac{( y - 2 ) ^{2}}{4 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (5, 2), a = 6, b = 4

y^{2} - 9 x^{2} - 4 y + 18 x = 86

y^{2} - 4 x^{2} + 8 x = 20 y + 4

\frac{x ^{2}}{4} - \frac{y ^{2}}{32} = 1

16 x^{2} - 9 y^{2} - 32 x + 36 y + 124 = 0

4 y^{2} - 3 x^{2} - 8 y + 6 x - 3 = 0

What is ((x-5)^2)/(36)-((y-2)^2)/(16)=1 ?
The solution to ((x-5)^2)/(36)-((y-2)^2)/(16)=1 is Hyperbola with (h,k)=(5,2),a=6,b=4