What is ((x-4)^2)/4-((y+1)^2)/9 =1 ?

The solution to ((x-4)^2)/4-((y+1)^2)/9 =1 is Hyperbola with (h,k)=(4,-1),a=2,b=3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

((x-4)^2)/4-((y+1)^2)/9 =1

\frac{( x - 4 ) ^{2}}{4} - \frac{( y + 1 ) ^{2}}{9} = 1

(h, k) = (4, - 1), a = 2, b = 3

Solution steps

\frac{( x - 4 ) ^{2}}{4} - \frac{( y + 1 ) ^{2}}{9} = 1

Rewrite

\frac{( x - 4 ) ^{2}}{4} - \frac{( y + 1 ) ^{2}}{9} = 1

in the form of a standard hyperbola equation

\frac{( x - 4 ) ^{2}}{2 ^{2}} - \frac{( y - ( - 1 ) ) ^{2}}{3 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (4, - 1), a = 2, b = 3

- 4 y^{2} + 9 x^{2} - 27 x - 16 y = 24

3 x^{2} - y^{2} - 18 x + 4 y + 20 = 0

- 9 x^{2} - 36 x + 16 y^{2} - 32 y - 164 = 0

9 X^{2} - Y^{2} + 54 X + 10 Y + 55 = 0

4 x^{2} - 9 y^{2} + 40 x - 72 y - 80 = 0

What is ((x-4)^2)/4-((y+1)^2)/9 =1 ?
The solution to ((x-4)^2)/4-((y+1)^2)/9 =1 is Hyperbola with (h,k)=(4,-1),a=2,b=3