What is ((4x^2-4y^2-4))/((x^2+y^2+1)^2)=0 ?

The solution to ((4x^2-4y^2-4))/((x^2+y^2+1)^2)=0 is Hyperbola with (h,k)=(0,0),a=1,b=1

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((4x^2-4y^2-4))/((x^2+y^2+1)^2)=0

\frac{( 4 x ^{2} - 4 y ^{2} - 4 )}{( x ^{2} + y ^{2} + 1 ) ^{2}} = 0

(h, k) = (0, 0), a = 1, b = 1

Solution steps

\frac{4 x ^{2} - 4 y ^{2} - 4}{( x ^{2} + y ^{2} + 1 ) ^{2}} = 0

Rewrite

\frac{4 x ^{2} - 4 y ^{2} - 4}{( x ^{2} + y ^{2} + 1 ) ^{2}} = 0

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{1 ^{2}} - \frac{( y - 0 ) ^{2}}{1 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 1, b = 1

f (x) (f (x)) = 2 x^{2} - 3 x + 2

\frac{y ^{2}}{21} - \frac{x ^{2}}{13} = 1

8 x^{2} - 15 = 4 y^{2} + 1

\frac{x ^{2}}{400} - \frac{y ^{2}}{441} = 1

11 x^{2} - 7 y^{2} + 44 x - 56 y - 145 = 0

What is ((4x^2-4y^2-4))/((x^2+y^2+1)^2)=0 ?
The solution to ((4x^2-4y^2-4))/((x^2+y^2+1)^2)=0 is Hyperbola with (h,k)=(0,0),a=1,b=1