What is 2500x^2-640x+41=y^2 ?

The solution to 2500x^2-640x+41=y^2 is Hyperbola with (h,k)=(16/125 ,0),a= 1/5 ,b= 1/250

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

2500x^2-640x+41=y^2

2500 x^{2} - 640 x + 41 = y^{2}

(h, k) = (\frac{16}{125}, 0), a = \frac{1}{5}, b = \frac{1}{250}

Solution steps

2500 x^{2} - 640 x + 41 = y^{2}

Rewrite

2500 x^{2} - 640 x + 41 = y^{2}

in the form of a standard hyperbola equation

\frac{( y - 0 ) ^{2}}{( \frac{1}{5} ) ^{2}} - \frac{( x - \frac{16}{125} ) ^{2}}{( \frac{1}{250} ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (\frac{16}{125}, 0), a = \frac{1}{5}, b = \frac{1}{250}

What is 2500x^2-640x+41=y^2 ?
The solution to 2500x^2-640x+41=y^2 is Hyperbola with (h,k)=(16/125 ,0),a= 1/5 ,b= 1/250