What is (x^2)/(50^2)-(y^2)/(25^2)=1 ?

The solution to (x^2)/(50^2)-(y^2)/(25^2)=1 is Hyperbola with (h,k)=(0,0),a=50,b=25

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x^2)/(50^2)-(y^2)/(25^2)=1

\frac{x ^{2}}{5 0 ^{2}} - \frac{y ^{2}}{2 5 ^{2}} = 1

(h, k) = (0, 0), a = 50, b = 25

Solution steps

\frac{x ^{2}}{5 0 ^{2}} - \frac{y ^{2}}{2 5 ^{2}} = 1

Rewrite

\frac{x ^{2}}{5 0 ^{2}} - \frac{y ^{2}}{2 5 ^{2}} = 1

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{5 0 ^{2}} - \frac{( y - 0 ) ^{2}}{2 5 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 50, b = 25

81 x^{2} - 64 y^{2} + 1134 x - 640 y - 2815 = 0

\frac{y ^{2}}{3} - \frac{x ^{2}}{16} = 1

2500 x^{2} - 640 x + 41 = y^{2}

5 x^{2} - 3 y^{2} + 31 x + 23 y + 24 = 0

y^{2} = \frac{( 900 + 36 ( x - 8 ) ^{2} )}{25}

What is (x^2)/(50^2)-(y^2)/(25^2)=1 ?
The solution to (x^2)/(50^2)-(y^2)/(25^2)=1 is Hyperbola with (h,k)=(0,0),a=50,b=25