(x^2)/(50^2)-(y^2)/(25^2)=1

解

\frac{x ^{2}}{5 0 ^{2}} - \frac{y ^{2}}{2 5 ^{2}} = 1

(h, k) = (0, 0), a = 50, b = 25

解答ステップ

\frac{x ^{2}}{5 0 ^{2}} - \frac{y ^{2}}{2 5 ^{2}} = 1

\frac{x ^{2}}{5 0 ^{2}} - \frac{y ^{2}}{2 5 ^{2}} = 1

を標準的な双曲線のequationで書き換える

\frac{( x - 0 ) ^{2}}{5 0 ^{2}} - \frac{( y - 0 ) ^{2}}{2 5 ^{2}} = 1

ゆえに双曲線の特性は:

(h, k) = (0, 0), a = 50, b = 25