What is ((x-5)^2)/(8^2)-((y-2)^2)/(6^2)=1 ?

The solution to ((x-5)^2)/(8^2)-((y-2)^2)/(6^2)=1 is Hyperbola with (h,k)=(5,2),a=8,b=6

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((x-5)^2)/(8^2)-((y-2)^2)/(6^2)=1

\frac{( x - 5 ) ^{2}}{8 ^{2}} - \frac{( y - 2 ) ^{2}}{6 ^{2}} = 1

(h, k) = (5, 2), a = 8, b = 6

Solution steps

\frac{( x - 5 ) ^{2}}{8 ^{2}} - \frac{( y - 2 ) ^{2}}{6 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (5, 2), a = 8, b = 6

4 y^{2} - x^{2} = 900

\frac{( x - 2.5 ) ^{2}}{2. 5 ^{2}} - \frac{( y - 5 ) ^{2}}{5 ^{2}} = 1

x^{2} - 2 y^{2} = - 1

2 x^{2} - 2 y^{2} - 20 x + 16 y - 16 = 0

x^{2} + 4 x - y^{2} = 0

What is ((x-5)^2)/(8^2)-((y-2)^2)/(6^2)=1 ?
The solution to ((x-5)^2)/(8^2)-((y-2)^2)/(6^2)=1 is Hyperbola with (h,k)=(5,2),a=8,b=6