What is x^2+4x-y^2=0 ?

The solution to x^2+4x-y^2=0 is Hyperbola with (h,k)=(-2,0),a=2,b=2

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x^2+4x-y^2=0

x^{2} + 4 x - y^{2} = 0

(h, k) = (- 2, 0), a = 2, b = 2

Solution steps

x^{2} + 4 x - y^{2} = 0

Rewrite

x^{2} + 4 x - y^{2} = 0

in the form of a standard hyperbola equation

\frac{( x - ( - 2 ) ) ^{2}}{2 ^{2}} - \frac{( y - 0 ) ^{2}}{2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 2, 0), a = 2, b = 2

(x + 5)^{2} - (y - 7)^{2} = 1

\frac{1}{2} y^{2} - 2 y = \frac{3}{2} x^{2} - 5 x

\frac{x ^{2}}{49} - \frac{y ^{2}}{44} = 1

x^{2} - y^{2} = 640

- \frac{1}{2} (\frac{x ^{2}}{2} - 100 x) + C = - 3 y^{2} + 150 y + C

What is x^2+4x-y^2=0 ?
The solution to x^2+4x-y^2=0 is Hyperbola with (h,k)=(-2,0),a=2,b=2