What is 2x^2-y^2=-8 ?

The solution to 2x^2-y^2=-8 is Hyperbola with (h,k)=(0,0),a=2sqrt(2),b=2

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2x^2-y^2=-8

2 x^{2} - y^{2} = - 8

(h, k) = (0, 0), a = 22, b = 2

Solution steps

2 x^{2} - y^{2} = - 8

Rewrite

2 x^{2} - y^{2} = - 8

in the form of a standard hyperbola equation

\frac{( y - 0 ) ^{2}}{( 2 2 ) ^{2}} - \frac{( x - 0 ) ^{2}}{2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 22, b = 2

x^{2} - y^{2} + 4 x - 2 y - 5 = 0

\frac{x ^{2}}{1} - \frac{y ^{2}}{15} = 1

x^{2} - 4 y^{2} + 6 x + 24 y - 31 = 0

x^{2} - 4 y^{2} - 6 x + 16 y + 21 = 0

\frac{x ^{2}}{36} - \frac{y ^{2}}{5} = 1

What is 2x^2-y^2=-8 ?
The solution to 2x^2-y^2=-8 is Hyperbola with (h,k)=(0,0),a=2sqrt(2),b=2