What is (-y^2)/4+(z^2)/4 =1-5/4 ?

The solution to (-y^2)/4+(z^2)/4 =1-5/4 is Hyperbola with (h,k)=(0,0),a=i,b=1

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(-y^2)/4+(z^2)/4 =1-5/4

\frac{- y ^{2}}{4} + \frac{z ^{2}}{4} = 1 - \frac{5}{4}

(h, k) = (0, 0), a = i, b = 1

Solution steps

\frac{- y ^{2}}{4} + \frac{z ^{2}}{4} = 1 - \frac{5}{4}

Rewrite

\frac{- y ^{2}}{4} + \frac{z ^{2}}{4} = 1 - \frac{5}{4}

in the form of a standard hyperbola equation

\frac{( z - 0 ) ^{2}}{i ^{2}} - \frac{( y - 0 ) ^{2}}{1 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = i, b = 1

+ y = x^{2} - y^{2}

m, x (x + 17) < 60 m (x)^{2}

x^{2} - 4 y^{2} + 2 x + 11 y - 7 = 0

\frac{y ^{2}}{25} - \frac{x ^{2}}{24} = 1

x^{2} - y^{2} - 2 x = 0

What is (-y^2)/4+(z^2)/4 =1-5/4 ?
The solution to (-y^2)/4+(z^2)/4 =1-5/4 is Hyperbola with (h,k)=(0,0),a=i,b=1