What is x^2-4y^2+2x+11y-7=0 ?

The solution to x^2-4y^2+2x+11y-7=0 is Hyperbola with (h,k)=(-1, 11/8),a=(sqrt(7))/4 ,b=(sqrt(7))/8

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x^2-4y^2+2x+11y-7=0

x^{2} - 4 y^{2} + 2 x + 11 y - 7 = 0

(h, k) = (- 1, \frac{11}{8}), a = \frac{7}{4}, b = \frac{7}{8}

Solution steps

x^{2} - 4 y^{2} + 2 x + 11 y - 7 = 0

Rewrite

x^{2} - 4 y^{2} + 2 x + 11 y - 7 = 0

in the form of a standard hyperbola equation

\frac{( x - ( - 1 ) ) ^{2}}{( \frac{7}{4} ) ^{2}} - \frac{( y - \frac{11}{8} ) ^{2}}{( \frac{7}{8} ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 1, \frac{11}{8}), a = \frac{7}{4}, b = \frac{7}{8}

\frac{y ^{2}}{25} - \frac{x ^{2}}{24} = 1

x^{2} - y^{2} - 2 x = 0

- 9 x^{2} + 25 y^{2} - 54 x - 50 y - 281 = 0

\frac{x ^{2}}{64} - \frac{y ^{2}}{- 39} = 1

x^{2} - y^{2} - 2 x - 2 y - 4 = 0

What is x^2-4y^2+2x+11y-7=0 ?
The solution to x^2-4y^2+2x+11y-7=0 is Hyperbola with (h,k)=(-1, 11/8),a=(sqrt(7))/4 ,b=(sqrt(7))/8