y^2-16x^2+64x-208=0

解

y^{2} - 16 x^{2} + 64 x - 208 = 0

(h, k) = (2, 0), a = 12, b = 3

解答ステップ

y^{2} - 16 x^{2} + 64 x - 208 = 0

y^{2} - 16 x^{2} + 64 x - 208 = 0

を標準的な双曲線のequationで書き換える

\frac{( y - 0 ) ^{2}}{1 2 ^{2}} - \frac{( x - 2 ) ^{2}}{3 ^{2}} = 1

ゆえに双曲線の特性は:

(h, k) = (2, 0), a = 12, b = 3